A function from to
is called even if for all
,
. We might call it even about the point
if, for all
,
.
Conversely, we can call a function strongly non-even if for all ,
,
.
Finding strongly non-even functions is easy, as any injective function provides a trivial example. We can make things harder for ourselves by considering only functions from to
. But now, it is just as easy to show that there are no strongly non-even functions.
Therefore, let’s make the following definition: Let a function be non-even of order
if, for all
,
. Thus, a strongly non-even function is non-even of order
, and a function being non-even of order
implies that it’s non-even of order
for all
.
In this paper, the set theorists Peter Komjáth and Saharon Shelah proved:
The existence of a non-even function of order 1 is equivalent to the Continuum Hypothesis (i.e., the statement that
).
Thus, if we assume that there is a non-even function of order 1, then we can conclude that . Can we weaken the hypothesis and still conclude something interesting? We can, as they also proved:
For any
, if there is a non-even function of order
, then
.